People who have spinning type weapons, I just want to do a bit of research.
How much do the discs have to weigh to cause damage/throw an opponent in the air? I suppose it depends on the power in the motor and other things, but surely theres a bandwidth of successful weights for such a weapon?
I'm just interested, might have a play around before next AWS.
Weapon research
Moderators: BeligerAnt, petec, administrator
-
- Posts: 3716
- Joined: Sun Apr 03, 2005 5:30 pm
- Location: Antrim, Northern Ireland
- Contact:
Weapon research
Die Gracefully Robotics
Winner - AWS 39
Winner - AWS 39
-
- Posts: 1134
- Joined: Tue Jan 20, 2004 12:00 am
- Location: London
- Contact:
Kwijebo's disc is 100g, however you need to get as much weight as possible at the rim, it will take longer to spin up however it will transfer more energy.
i think this is too much weight in the disc, some others have a range from 25g to 65g.
I built kwijebo arround the disc, however a better approach would be to build an ant then see how much weight you have left over.
i think this is too much weight in the disc, some others have a range from 25g to 65g.
I built kwijebo arround the disc, however a better approach would be to build an ant then see how much weight you have left over.
TEAM GEEK!
- BeligerAnt
- Posts: 1872
- Joined: Wed May 15, 2002 12:00 am
- Location: Brighton
- Contact:
It's all about inertia.
To increase inertia, concentrate the mass towards the rim (for a given size of disc).
Inertia depends on disc diameter (and mass as above).
From this point it is possible to get completely sucked into the maths and calculate (theoretically) how far your disc will throw your opponent - only to find out that they knock you out of the arena first!
The downside is the bigger the inertia, the longer the disc takes to spin up. (Since inertia is resistance to change - it doesn't want to start to spin, but once it's spinning, it don't wanna stop!)
To increase inertia, concentrate the mass towards the rim (for a given size of disc).
Inertia depends on disc diameter (and mass as above).
From this point it is possible to get completely sucked into the maths and calculate (theoretically) how far your disc will throw your opponent - only to find out that they knock you out of the arena first!

The downside is the bigger the inertia, the longer the disc takes to spin up. (Since inertia is resistance to change - it doesn't want to start to spin, but once it's spinning, it don't wanna stop!)
Last edited by BeligerAnt on Sat Jan 06, 2007 7:35 pm, edited 1 time in total.
Gary, Team BeligerAnt
- BeligerAnt
- Posts: 1872
- Joined: Wed May 15, 2002 12:00 am
- Location: Brighton
- Contact:
The inertia of a disc is I = 0.5 * M * R^2
Where M is mass, R is radius, and ^2 is "to the power of 2" or "squared"
The kinetic energy stored in the disc is E = 0.5 * I * w^2
Where I is inertia and w (omega) is angular velocity.
Note mass is in kg, radius is in metres(!) and w is in radians/sec
To get more ant-friendly units, I = 0.5 * 10^-9 * m * r^2
with m in grams, r in mm
w = 2 * pi * (revs per sec) or
w = (pi / 30) * (revs per min)
So E = ((pi^2)/1800) * I * RPM^2
Or, E = 2.74 * 10^-12 * m * r^2 * RPM^2
So Randar's 20g 80mm (diameter) disc at 10000rpm would store about 8.77 Joules - enough to throw a 150g robot some distance!
Since r and RPM are squared, they provide a bigger increase in energy than simply increasing the mass. Concentrating the mass towards the edge of the disc increases the inertia towards a theoretical limit of M * R^2 (i.e. twice as much as a plain disc)
Where M is mass, R is radius, and ^2 is "to the power of 2" or "squared"
The kinetic energy stored in the disc is E = 0.5 * I * w^2
Where I is inertia and w (omega) is angular velocity.
Note mass is in kg, radius is in metres(!) and w is in radians/sec
To get more ant-friendly units, I = 0.5 * 10^-9 * m * r^2
with m in grams, r in mm
w = 2 * pi * (revs per sec) or
w = (pi / 30) * (revs per min)
So E = ((pi^2)/1800) * I * RPM^2
Or, E = 2.74 * 10^-12 * m * r^2 * RPM^2
So Randar's 20g 80mm (diameter) disc at 10000rpm would store about 8.77 Joules - enough to throw a 150g robot some distance!
Since r and RPM are squared, they provide a bigger increase in energy than simply increasing the mass. Concentrating the mass towards the edge of the disc increases the inertia towards a theoretical limit of M * R^2 (i.e. twice as much as a plain disc)
Gary, Team BeligerAnt
-
- Posts: 308
- Joined: Sat Jul 19, 2003 12:00 am
- Location: Netherlands
8.77 Joule, hmmm.
Using the old DBA specs (35gr, 90mm, 16krpm) i get 46.755 Joules
Using the new DBA specs (42gr, 60mm, 30krpm) i get 93.29 Joules, but since the mass is more distributed towards the outer ring it's more like 100 Joule,
Doing some simple calculations E=m*g*h (m=0.150, g=9.81) we get h= 68 meter, lol
Using the old DBA specs (35gr, 90mm, 16krpm) i get 46.755 Joules
Using the new DBA specs (42gr, 60mm, 30krpm) i get 93.29 Joules, but since the mass is more distributed towards the outer ring it's more like 100 Joule,
Doing some simple calculations E=m*g*h (m=0.150, g=9.81) we get h= 68 meter, lol